NOI.AC

ID	题目	提交者	结果	用时	内存	语言	文件大小	提交时间	测评时间
#206463	#1745. 一元三次方程求解	ylq0221	100	0ms	1288kb	C++11	340b	2024-07-22 19:16:41	2024-07-22 20:13:09

answer

#include <bits/stdc++.h>
using namespace std;
int main(){
	int cnt=0;
	double a,b,c,d;
	cin>>a>>b>>c>>d;
	for(double i=-100;i<=100;i+=0.001){
		double x=a*i*i*i+b*i*i+c*i+d;
		double t=i+0.001;
		double y=a*t*t*t+b*t*t+c*t+d;
		if((x*y)<=0){
			printf("%.2lf ",(i+t)/2);
			cnt++;
		}
		if(cnt==3) return 0;
	}
	return 0;
}

源文件, 语言: C++11

详细

小提示：点击横条可展开更详细的信息

Test #1:

score: 25

Accepted

time: 0ms

memory: 1280kb

input:

1 -2 -1 2

output:

-1.00 1.00 2.00

result:

ok single line: '-1.00 1.00 2.00 '

Test #2:

score: 25

Accepted

time: 0ms

memory: 1284kb

input:

1 -4.65 2.25 1.4

output:

-0.35 1.00 4.00

result:

ok single line: '-0.35 1.00 4.00 '

Test #3:

score: 25

Accepted

time: 0ms

memory: 1284kb

input:

1 10 -1 -10

output:

-10.00 -1.00 1.00

result:

ok single line: '-10.00 -1.00 1.00 '

Test #4:

score: 25

Accepted

time: 0ms

memory: 1288kb

input:

1 -1.8 -8.59 -0.84

output:

-2.10 -0.10 4.00

result:

ok single line: '-2.10 -0.10 4.00 '