ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#206497 | #1745. 一元三次方程求解 | kevinwww188 | 100 | 0ms | 1284kb | C++11 | 253b | 2024-07-22 20:10:28 | 2024-07-22 20:10:50 |
answer
#include<bits/stdc++.h>
using namespace std;
int main(){
double a,b,c,d;
cin>>a>>b>>c>>d;
for(double i=-100.00;i<=100.00;i+=0.01){
double j=i+0.01;
if((a*i*i*i+b*i*i+c*i+d)*(a*j*j*j+b*j*j+c*j+d)<0)
printf("%.2f ",j);
}
return 0;
}
详细
小提示:点击横条可展开更详细的信息
Test #1:
score: 25
Accepted
time: 0ms
memory: 1280kb
input:
1 -2 -1 2
output:
-1.00 1.00 2.00
result:
ok single line: '-1.00 1.00 2.00 '
Test #2:
score: 25
Accepted
time: 0ms
memory: 1284kb
input:
1 -4.65 2.25 1.4
output:
-0.35 1.00 4.00
result:
ok single line: '-0.35 1.00 4.00 '
Test #3:
score: 25
Accepted
time: 0ms
memory: 1284kb
input:
1 10 -1 -10
output:
-10.00 -1.00 1.00
result:
ok single line: '-10.00 -1.00 1.00 '
Test #4:
score: 25
Accepted
time: 0ms
memory: 1284kb
input:
1 -1.8 -8.59 -0.84
output:
-2.10 -0.10 4.00
result:
ok single line: '-2.10 -0.10 4.00 '